Guaranteed Accomplishment with Newest Jan-2025 FREE Oracle 1z0-808 [Q96-Q114]

Guaranteed Accomplishment with Newest Jan-2025 FREE Oracle 1z0-808

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NEW QUESTION # 96
Given:

What three modifications, made independently, made to class greet, enable the code to compile and run?

A. line 6 replaced with handy.dandy.keystroke stroke = new KeyStroke ( );
B. import handy.dandy.KeyStroke.typeException(); added before line 1
C. import handy.dandy.*; added after line 1
D. line 6 replaced with handy.dandy.KeyStroke Stroke = new handy.dandy.KeyStroke();
E. import handy.*; added before line 1
F. line 6 replaced with handy.*.KeyStroke = new KeyStroke ( );
G. import handy.dandy,KeyStroke; added after line 1

Answer: C,D,G

Explanation:
Three separate solutions:
C: the full class path to the method must be stated (when we have not imported the package)
D: We can import the hold dandy class
F: we can import the specific method

NEW QUESTION # 97
Given:

What is the result?

A. Option D
B. Option C
C. Option B
D. Option A

Answer: C

NEW QUESTION # 98
Given the code fragment:

Assume that the system date is June 20, 2014. What is the result?

A.
B. An exception is thrown at runtime.
C. Compilation fails.
D.

Answer: D

NEW QUESTION # 99
Given the code fragment:

What is the result?

A. 0
B. Compilation fails.
C. 1
D. 2

Answer: D

NEW QUESTION # 100
Given the code fragment:
public class Test {
static String[][] arr =new String[3][];
private static void doPrint() {
//insert code here
}
public static void main(String[] args) {
String[] class1 = {"A","B","C"};
String[] class2 = {"L","M","N","O"};
String[] class3 = {"I","J"};
arr[0] = class1;
arr[1] = class2;
arr[2] = class3;
Test.doPrint();
}
}
Which code fragment, when inserted at line //insert code here, enables the code to print COJ?

A. private static void doPrint() {
for (int i = 0;i < arr.length;i++) {
int j = arr[i].length-1;
System.out.print(arr[i][j]);
}
}
B. for (int i = 0;i < arr.length-1;i++) {
int j = arr[i].length-1;
System.out.print(arr[i][j]);
i++;
}
C. int i = 0;
for (String[] sub: arr[][]) {
int j = sub.length;
System.out.print(arr[i][j]);
i++;
}
D. int i = 0;
for (String[] sub: arr) {
int j = sub.length -1;
for (String str: sub) {
System.out.println(str[j]);
i++;
}
}

Answer: A

Explanation:
Incorrect:
not A: The following line causes a compile error:
System.out.println(str[j]); Not C: Compile erro line: for (String[] sub: arr[][]) not D: Output: C

NEW QUESTION # 101
Given the code fragment:
System.out.printIn("Result: " + 2 + 3 + 5);
System.out.printIn("Result: " + 2 + 3 * 5);
What is the result?

A. Result: 10 Result: 30
B. Result: 10 Result: 25
C. Compilation fails
D. Result: 215 Result: 215
E. Result: 235 Result: 215

Answer: E

Explanation:
First line:
System.out.println("Result: " + 2 + 3 + 5);
String concatenation is produced.
Second line:
System.out.println("Result: " + 2 + 3 * 5);
3*5 is calculated to 15 and is appended to string 2. Result 215.
The output is:
Result: 235
Result: 215
Note #1:
To produce an arithmetic result, the following code would have to be used:
System.out.println("Result: " + (2 + 3 + 5));
System.out.println("Result: " + (2 + 1 * 5));
run:
Result: 10
Result: 7
Note #2:
If the code was as follows:
System.out.println("Result: " + 2 + 3 + 5");
System.out.println("Result: " + 2 + 1 * 5");
The compilation would fail. There is an unclosed string literal, 5", on each line.

NEW QUESTION # 102
Given the code fragment:

What is the result?

A. s-1
B. S 6
C. w 7
D. S 5

Answer: A

Explanation:

NEW QUESTION # 103
Given:

What is the result?

A. Option D
B. Option C
C. Option B
D. Option A

Answer: C

NEW QUESTION # 104
Given the code fragment:

Test.java:

Which is the result?

A. Option E
B. Option D
C. Option B
D. Option C
E. Option A

Answer: A

NEW QUESTION # 105
Given the code fragment:

Which modification enables the code to print 54321?

A. Replace line 6 with --x; and, at line 7, insert system, out. print (x);
B. Replace line 6 with System, out. print (--x) ;
C. Replace line 12 With return (x > 0) ? false: true;
D. At line 7, insert x --;

Answer: B

NEW QUESTION # 106
Given the code fragment:

What is the result?

A. 0
B. 1
C. 2
D. 3

Answer: D

Explanation:

NEW QUESTION # 107
Given the code fragment:

What is the result?

A. Found Red Found Blue
B. Found Red Found Blue Found White
C. Found Red Found Blue Found White Found Default
D. Found Red

Answer: A

Explanation:
As there is no break statement after the case "Red" statement the case Blue
statement will run as well.
Note: The body of a switch statement is known as a switch block. A statement in the switch block can be labeled with one or more case or default labels. The switch statement evaluates its expression, then executes all statements that follow the matching case label.
Each break statement terminates the enclosing switch statement. Control flow continues with the first statement following the switch block. The break statements are necessary because without them, statements in switch blocks fall through: All statements after the matching case label are executed in sequence, regardless of the expression of subsequent case labels, until a break statement is encountered.

NEW QUESTION # 108
Which one of the following code examples uses valid Java syntax?

A. Option A
B. Option D
C. Option B
D. Option C

Answer: A

NEW QUESTION # 109
Given the following code fragment:

What is the result if the integer value is 33?

A. The fox lazy ...
B. Quick fox over lazy ...
C. Quick fox the ....
D. The fox jump lazy ...

Answer: A

Explanation:
33 is greater than 0.
33 is not equal to 0.
the is printed.
33 is greater than 30
fox is printed
33 is greater then 10 (the two else if are skipped)
lazy is printed finally ... is printed.

NEW QUESTION # 110
Given:

What is the result?